y^(-1/2)=1/3

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Solution for y^(-1/2)=1/3 equation: 


D( y )

y = 0

y < 0

y = 0

y = 0

y < 0

y in (0:+oo)

y^(-1/2) = 1/3 // - 1/3

y^(-1/2)-(1/3) = 0

y^(-1/2)-1/3 = 0

1*y^(-1/2) = 1/3 // : 1

y^(-1/2) = 1/3

-1/2 < 0

1/(y^(1/2)) = 1/3 // * y^(1/2)

1 = 1/3*y^(1/2) // : 1/3

3 = y^(1/2)

y^(1/2) = 3 // ^ 2

y = 9

y = 9

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